**2** answer

Therefore,

\[\varepsilon =\oint{d\varepsilon =\int_{0}^{R}{Bvdr=\int\limits_{0}^{R}{B\omega rdr=\frac{B\omega \mathop{R}^{2}}{2}}}}\]

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Therefore,

\[\varepsilon =\oint{d\varepsilon =\int_{0}^{R}{Bvdr=\int\limits_{0}^{R}{B\omega rdr=\frac{B\omega \mathop{R}^{2}}{2}}}}\]

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