1200kg steel beam is supported by two ropes. What is the Tension of rope 1?
A 1200kg steel beam is supported by two ropes. What is the Tension of rope 1 and rope 2?
the picture of it is provided below. Where do i begin? Do i start with cos and sin? please help thank you
2 answer
Let T1 = tension in rope 1 and T2 tension is rope 2.
Summation of forces along the y-axis = 0
T1y + T2y - W = 0
T1cos 20 + T2cos 30 - 1200kg(9.8 m/s^2) = 0
cos 20T1 + cos 30T2 = 11760 N eq. 1
Summation of forces along the x-axis = 0
T1x + T2x = 0
-T1sin20 + T2sin30 = 0
T2 = T1sin20/sin30
T2 = T1(0.68404) eq. 3
Substitute eq. 3 in eq. 1:
cos20T1 + cos30(T1(0.68404) = 11760 N
1.52309T1 = 11760 N
T1 = 11760 N/1.52309
T1 = 7721.1 N answer
T2 = (7721.1 N)(0.68404) = 5281.5 N answer
Hope this helps.
Summation of forces along the y-axis = 0
T1y + T2y - W = 0
T1cos 20 + T2cos 30 - 1200kg(9.8 m/s^2) = 0
cos 20T1 + cos 30T2 = 11760 N eq. 1
Summation of forces along the x-axis = 0
T1x + T2x = 0
-T1sin20 + T2sin30 = 0
T2 = T1sin20/sin30
T2 = T1(0.68404) eq. 3
Substitute eq. 3 in eq. 1:
cos20T1 + cos30(T1(0.68404) = 11760 N
1.52309T1 = 11760 N
T1 = 11760 N/1.52309
T1 = 7721.1 N answer
T2 = (7721.1 N)(0.68404) = 5281.5 N answer
Hope this helps.
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